Question

5^(x-3)*3^(2x-8)=225

Answer 1

$5^{x-3}\cdot 3^{2x-8}=225$
$5^{x-3}\cdot 3^{2(x-4)}=225$
$5^{x-3}\cdot (3^2)^{x-4}=225$
$5^{x-3}\cdot 9^{x-4}=225$

In view of getting same exponent on both terms on left hand side, divide $5$ each side :
$\dfrac{5^{x-3}\cdot 9^{x-4}}{5}=\dfrac{225}{5}$

$5^{x-4}\,\cdot\,9^{x-4}=45$

$(5\,\cdot\,9)^{x-4}=45$

$45^{x-4}=45^1$

Since the bases are equal, exponents also must be equal :
$x-4=1\\x=5$

Answer 2

Answer:

⇒ X = 5

Step-by-step explanation:

Refer to the attachment ^^