5^x-3 ×3^2x-8=225, proof x=5
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Answered by
1
Hey mate !!
Here's the answer !!
Let us assume the powers to be equal in both the cases.
=> x - 3 = 2x - 8
So since powers are same we can multiply the bases.
( 5 * 3 ) ^ x - 3 = 225
=> ( 15 ) ^ x - 3 = 225
We know that 225 = 15 ^ 2
So we can write 225 in the form of exponents. We get,
= ( 15 ) ^ x - 3 = ( 15 ) ^ 2
Bases are same, so equate the powers. We get,
x - 3 = 2
=> x = 2 = 3 = 5
Hence x = 5
Now substitute value of x and check whether the powers are equal which we assumed.
x - 3 = 2x - 8
Substituting x = 5, we get,
5 - 3 = 2 ( 5 ) - 8
2 = 10 - 8
2 = 2
Hence our assumption was right.
Hence proved.
Hope my answer helps !!
Cheers !!
Here's the answer !!
Let us assume the powers to be equal in both the cases.
=> x - 3 = 2x - 8
So since powers are same we can multiply the bases.
( 5 * 3 ) ^ x - 3 = 225
=> ( 15 ) ^ x - 3 = 225
We know that 225 = 15 ^ 2
So we can write 225 in the form of exponents. We get,
= ( 15 ) ^ x - 3 = ( 15 ) ^ 2
Bases are same, so equate the powers. We get,
x - 3 = 2
=> x = 2 = 3 = 5
Hence x = 5
Now substitute value of x and check whether the powers are equal which we assumed.
x - 3 = 2x - 8
Substituting x = 5, we get,
5 - 3 = 2 ( 5 ) - 8
2 = 10 - 8
2 = 2
Hence our assumption was right.
Hence proved.
Hope my answer helps !!
Cheers !!
Answered by
1
Answer:
⇒x = 5
Step-by-step explanation:
Refer to the attachment^^
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