5(x+3)=3y, 2x-y=0 by using substitution method step by step
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5(x+3) = 3y
5x + 15 = 3y -- eqn (1)
2x - y =0 -- eqn(2)
Rearranging eqn 1 , we get ,
y = (5x + 15) / 3 -- eqn (3)
Substituting eqn3 in eqn 2 ,
2x - (5x + 15) / 3 =0
6x - 5x + 15 = 0 [ taking LCM and transposing]
x = -15
Putting value of x in eqn3,
y = (-75 + 15) / 3
y = - 60 / 3
HENCE , y = -20
X = -15 and Y = -20
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