Question

5(x+3)=3y, 2x-y=0 by using substitution method step by step​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

5(x+3) = 3y

5x + 15 = 3y -- eqn (1)

2x - y =0 -- eqn(2)

Rearranging eqn 1 , we get ,

y = (5x + 15) / 3 -- eqn (3)

Substituting eqn3 in eqn 2 ,

2x - (5x + 15) / 3 =0

6x - 5x + 15 = 0 [ taking LCM and transposing]

x = -15

Putting value of x in eqn3,

y = (-75 + 15) / 3

y = - 60 / 3

HENCE , y = -20

X = -15 and Y = -20