Question

5 ( x – 5 ) = 4 ( x + 4 )

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

We have given Equation: 5(x-5)= 4(x+4)

How to solve ?

Step 1: firstly we have to expand the terms by opening the brackets.

Step 2: Multiply each and every term and make Variable terms together and constant term together.

Step 3: Evaluate it and shifts all constant to constant side and let the Variable alone.

➙5(x-5)=4(x+4)

➙5x-25= 4x+16

solve for x

➙5x-4x-25= 16

➙x-25= 16

Solve for constant

➙x= 16+25

➙x=41

x= 41

Check:

➙5(x-5)=4(x+4)

➙5(41-5)= 4(41+4)

➙5× 36= 4×45

➙180=180

Hence,x= 41 satisfied terms of both sides.

Since,LHS = RHS(Verified)

Answer 2

☯ GIVEN :

• $\bf{5(x - 5) =4(x+4)}$

☯ TO FIND :

• The value of x.

➲SOLUTION :

$\implies \sf{5(x - 5) =4(x+4)}$

$\implies\sf{5x-25 = 4x +16}$

• Transposing -25 to Right side and 4x to left side :

$\implies\sf{ 5x-4x= 16+25}$

$\implies \underline{ \boxed {\red {\bf{ x = 41}}}}$

$\huge{\red {\therefore }}$ The value of x is 41.

✞VERIFICATION :

• Substituting the value of x :

$\implies \sf{5(x - 5) =4(x+4)}$

$\implies \sf{5(41 - 5) =4(41+4)}$

$\implies \sf{5\times 36 =4\times 45}$

$\implies \sf{180 =180}$

$\implies \underline{ \boxed {\red {\bf{LHS = RHS}}}}$

$\huge{\red {\therefore }}$ Verified.