Question

5 x square - 8 x minus 4 when X belongs to q

Answer 1

$\bold{Answer :}$

Now,

5x² - 8x - 4

= 5x² - (10 - 2)x - 4

= 5x² - 10x + 2x - 4

= 5x (x - 2) + 2 (x - 2)

= (x - 2) (5x + 2),

which is the required factorization

The zeroes of the given polynomial
are 2 and (- 2/5)

#$\bold{MarkAsBrainliest}$

Answer 2

5x² - 8x - 4 

By splitting - 8x as - 10x + 2x

5x² - 10x + 2x - 4

5x(x - 2) + 2(x - 2)

(x - 2) (5x + 2)

As belongs to q we have to take both (x - 2) and (5x + 2) as factors

Hope this helps you.