Question

5 years ago a man was 7 times as old as his son. after 5 years he will be thrice as old as his son. find their present ages

Answer 1

Let the son age be x Man age = y 5 years ago x-5,y-5 y-5=7(x-5) y-5=7x-35 7x-y=30......(1) After 5 years x+5,y+5 y+5=3(x+5) y+5=3x+15 y-3x=10......(2) On Adding equations 1 and 2, we get 4x=40 x=10 Putting the value of x in equation 2 y-30=10 y=30+10 y=40  Man's Age=40 years Son's Age=10 years

Answer 2

Select it as Brainlist please