Question

5 years ago a man was 7 times as old as his son. after 5 years he will be thrice as old as his son find their present ages

Answer 1

I think this is helpful for you

Answer 2

Heya mate,Here is ur answer

Let the present age of man be x.

Five years ago, his age = x-5

Let son's age be y.

5 years ago son's age=y-5

A/Q

x-5=7(y-5)

x-5=7y-35

x=7y-35+5

x=7y-30-------(1)

After 5 years,

Man's age=x+5

Son's age = y+5

A/Q

x+5=3(y+5)

x+5=3y+15

x=3y+15-5

x=3y+10--------(2)

From equation 1 and 2

7y-30=3y+10

7y-3y=10+30

4y=40

y=40/4

y=10

x= 3y+10

x=3×10+10

x=30+10

x=40

$<b>So, present age of man = 40 years and son's=10 years.</b>$

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@Laughterqueen

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