Question

5 years ago a man was 7 times as old his son.5 years hence the father will be three times as old as his son. find present age of son & Father.

Answer 1

Let present age of son = X
Age of son before 5 years = X-5
So, Present age of father = 7(X-5)+5 ……… (i) 
Age of son after 5 years = X+5
Age of father after 5 years = 3(X+5)
So, present age of father = 3(X+5)-5 ……….(ii) 
Equating age of father i.e. (i) and (ii) 
7(X- 5)+5 = 3(X+ 5)-5
7X – 35+5 = 3X + 15-5


7X-3X = 15 - 5 + 35 - 5
4X = 40
X = 40/4
X (son)= 10 , Father (3(10+5)-5)= 40 yrs 
Hope the answer will satisfy you

Answer 2

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