5 years ago A was thrice as old as B. 10 years later A will be twice as old as B. what are the present ages of A B?
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Let age of A = x
Let age of B = y
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = - 15 + 5
x - 3y = - 10
x = - 10 + 3y --------(1)
x + 10 = 3(y + 10)
x + 10 = 3y + 30
x - 3y = 30 - 10
x - 3y = 20 --------(2)
Put (1) in (2)
- 10 + 3y - 3y = 20
- 10 = 20
No, Solution.
Let age of B = y
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = - 15 + 5
x - 3y = - 10
x = - 10 + 3y --------(1)
x + 10 = 3(y + 10)
x + 10 = 3y + 30
x - 3y = 30 - 10
x - 3y = 20 --------(2)
Put (1) in (2)
- 10 + 3y - 3y = 20
- 10 = 20
No, Solution.
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