Question

5 years ago, man was 7 times as old as his son.After 5 years he will be thrice as old as his son.Find the present age.

Answer 1

Hey!!!
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●Sons age 5 years ago=x father's age = 7x
》So,Their present age = x+5 and 7x+5 respectively
》Sons age 5 years hence = x+10(since x is sons age 5 years ago from present age and we are talking of his age 5 years hence from his present age so 5+5=10)
》Fathers age 5 years hence =3(x+10)
》Hence, fathers present age will be 3(x+10)-5
》Also fathers present age =7x+5
》Therefore 7x+5=3(x+10)-5
》7x+5=3x+30-5
》7x-3x=25-5
》4x=20
》x=5
》Sons age 5 years ago= 5years fathers age = 5×7=35years
》Present age of the son= 10years(5+5) fathers age=35+5=40 years
》Sons age 5 years hence= 5+10=15years fathers age= 3×(5+10)=45 years
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Hope it helps!!! :)