Math, asked by goldiee13, 1 year ago

5 years ago, Priya was twice as old as prerna .10 years later priya's age will be 10 years more than Prerna .find their present age ?

Answers

Answered by Anonymous
2
                      Priya                                                           Prerna
present age    x                                                                     y
5 years ago    x-5                                                                  y-5
10 years later x+10                                                                y+10
according to question
x-5=2(y-5)
x-5=2y-10
x=2y-10+5
x=2y-5 equation  1

x+10=y+10+10
x+10=y+20
x-y-20+10=0
x-y-10=0 equation 2

put value of equation 1 in equation 2
2y-5-y-10=0
y-15=0
y=15
put this value in equation 1
x=2*15-5
x=30-5
x=25

Answered by aketolI
0
Let prerna age be x years
Priya age be 2x
5 years ago,
Prerna age =x-5
Priya age = 2x-5
10 years later,
Prerna age =(x-5+10) =x+5 yrs
Priya age=(2x-5+10) =2x+5 yrs
As per question,
2x+5=x+5+10
2x-x=5+10-5
X=15-5
X=10
So, prerna age =10 yrs
Priya = 2x
=2*10
= 20 yrs
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