Question

50.0 kg of N2 and 10 kg of H2 are mixed to produce NH3. calculate the energy NH3 formed. Identify the limiting reagent in the production of NH3 in this situation
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Answer 1

Hii it's my punishment.......

I done it now............

Answer 2

Answer:

N2 + 3H2 ---->2NH3

here.

28kg N reacts with 6kg of H

so,

50 kg of M react with 6/28×50kg H = 10.7kg but we have only 10 so H2 is limiting reagent..

6kg H2 gives 34kg NH3

10kg H2 will give 34/6×10=56.67kgNH3

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