50 circular discs, each of radius 7cm and thickness 0.5cm are placed one above the
other. Find the total surface area of the solid so formed. Find how much space will
be left in a cubical box of side 25cm if the solid formed is placed inside it.
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Answers
Answered by
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Hi!!! Here is ur answer.
The solid formed is a cylinder.
Since the radius of the cylinder is same as the radius of the one circular plate.
The radius of the base of the cylinder be r = 7 cm
The height of the cylinder is same as the thickness of 50 circular plates.
Thickness of 1 plate = 0.5 cm.
The height of the cylinder h
= 50*0.5 =25 cm
Total surface area of the cylinder = curved surface area of the cylinder + 2*area of the base
2πrh + 2πr^2
2πr(r+h)
=2×22/7×7(7+25)
=1408cm^2
Volume of the cylinder = πr^2h
=22/7×7×7×25
=3850cm^3
Space left in a cubical box=Volume of box−volume of solid
=25^3−3850
=15625−3850
=11775cm^3
Hope it helps
CoruscatingGarçon:
Because if we join several circles one over other we get a cylinder
For TSA of cylinder we have formula-
Total surface area of the cylinder = curved surface area of the cylinder + 2*area of the base
Area of base is πr^2 which is the area of a circle too
thx a lot
I'm having a small doubt...can we take the area of a circle *50 ?
PLS ANS. TO MY QSTN..!
No
Brainliest pls
how to make it brinlist
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