50 circular plates each of radius 7cm and thickness 1/2 cm are placed one above another to form a solid right circular cylinder.find total surface area and volume of cylinder so formed
Answers
Answered by
402
Solution:-
Since the radius of the cylinder is same as the radius of the circular plate.
So, the radius of the base of the cylinder = 7 cm
Height of the cylinder is same as the thickness of 50 circular plates.
Thickness of 1 plate = 1/2 cm
Then, thickness of 50 plates = 50*1/2
= 25 cm
Height of the cylinder = 25 cm
Total surface area of cylinder = 2πr(r+h)
= 2*22/7*7(7+25)
= 44*32
Total surface area of the cylinder = 1408 sq cm
Volume of the cylinder = πr²h
= 22/7*7*7*25
= 3850 cu cm
Volume of the cylinder is 3850 cu cm
Answer.
Since the radius of the cylinder is same as the radius of the circular plate.
So, the radius of the base of the cylinder = 7 cm
Height of the cylinder is same as the thickness of 50 circular plates.
Thickness of 1 plate = 1/2 cm
Then, thickness of 50 plates = 50*1/2
= 25 cm
Height of the cylinder = 25 cm
Total surface area of cylinder = 2πr(r+h)
= 2*22/7*7(7+25)
= 44*32
Total surface area of the cylinder = 1408 sq cm
Volume of the cylinder = πr²h
= 22/7*7*7*25
= 3850 cu cm
Volume of the cylinder is 3850 cu cm
Answer.
Answered by
192
Radius of the cylinder=radius of the plate=r=7cm
Height of the cylinder=h= No. of plates × thickness of one plate=50×1/2 =25 cm
∴, total surface area= curved surface area+ 2×area of tha base
=2πrh+2πr²
=2πr(h+r)
=2×22/7×7(25+7)
=44×32
=1408 cm²
Volume of the cylinder
=πr²h
=22/7×7²×25
=22×7×25
=3850 cm³
∴, total surface area is 1408 cm² and volume is 3850 cm³. Ans.
Height of the cylinder=h= No. of plates × thickness of one plate=50×1/2 =25 cm
∴, total surface area= curved surface area+ 2×area of tha base
=2πrh+2πr²
=2πr(h+r)
=2×22/7×7(25+7)
=44×32
=1408 cm²
Volume of the cylinder
=πr²h
=22/7×7²×25
=22×7×25
=3850 cm³
∴, total surface area is 1408 cm² and volume is 3850 cm³. Ans.
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