Question

prove that :(1+tan 2A)cot A ÷Cosec 2A=tan A.....its urgent

Answer 1

Answer:

(1+tan 2A)cot A /Cosec 2A=tan A

= sec^2A.cot^2A/cosec^2A=tanA

= 1/cos^2A.cosA/sinA /1/sin^2A

= sin^2A/sinA.cosA

= sinA/cosA

= tanA

I HOPE IT HELPS UHH...

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Answer 2

Answer:

$\frac{(1+tan^{2}A)cotA}{cosec^{2}A}=tanA$

Step-by-step explanation:

$LHS=\frac{(1+tan^{2}A)cotA}{cosec^{2}A}\\=\frac{sec^{2}A cotA}{cosec^{2}A}$

/* By Trigonometric identity:

1+tan²A= sec²A */

$=\frac{\frac{1}{cos^{2}A}}{\frac{1}{sin^{2}A}} cotA\\=\frac{sin^{2}A}{cos^{2}A}\times cotA\\</p><p>= tan^{2}A cotA\\=tanA(tanAcotA)\\=tanA\times 1\\=tanA\\=RHS$

Therefore,

$\frac{(1+tan^{2}A)cotA}{cosec^{2}A}=tanA$

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