Question

. 50 g of a hot solid of specific heat capacity 0.25 Jg-' °C- and at 100°C is placed in 80 g of cold water
Calculate the initial temperature of cold water.
the temperature of cold water rises by (3°C Find the initial temperature of cold water.​

Answer 1

Answer:

Initial temperature: 16.36°C

Explanation:

T=100°C

Let Ф be final temperature

fall in temp.=(100-0)°C

cold water at t°C

m=80 g                    C=4.2

rise in temp.=Ф-t=3

Heat lost by hot solid =heat gained by water

MCs(T-Ф)=mcw(Ф-t)

50* 1/4(100-Ф)= 80*42/10*3

25/2Ф=242

Ф=19.36

But,Ф-3

so

temp. =16.36°C

Answer 2

Answer:

సాయంకాలం

Explanation:

గౌతముడుmxxx ఫక్