Question

50 g
of CaCo3 is allowed to react with 70g
of H₃ PO4 Calculate :
1. amount of Ca3(PO) 4 formed.
2. amount of unreacted
unreacted reagent​

Answer 1

Explanation:

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11th

Chemistry

Some Basic Concepts of Chemistry

Stoichiometry and Stoichiometric Calculations

50 g of { CaCO }_{ 3 } is...

CHEMISTRY

50 g of CaCO

3

is allowed to react with 70 g of H

3

PO

4

. Calculate :

(i) amount of Ca

3

(PO

4

)

2

formed

(ii) amount of unreacted reagent

December 26, 2019

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Jenny Sagani

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ANSWER

2:3:1

2H

3

PO

4

+3CaCO

3

⟶Ca

3

(PO

4

)

2

+3H

2

0+3CO

2

1mol=98g1mol=100g

70g50g

=

7

5

mol=

2

1

mol

For

2

1

molCaCo

3

,weneed

3

2

×

2

1

=

3

1

molH

3

PO

4

∴Ca

3

(PO

4

)

2

formed=

2

1

×

3

1

=

6

1

moles

=

6

1

×310g

=51.66g

unreactedH

3

PO

4

=

7

5

−

3

1

=

21

8

moles

=

21

8

×98=37.33g