Question

50 g of CaCO3 is allowed to react with 73.5 g of H3PO4 . Calculate : (i) Amount of unreacted reagent (in moles)

Answer 1

Answer:

3 CaCO3 +2 H3PO4 ⇒ Ca3( PO4 )2 +3 H2CO3

   300 g            196 g

    50 g of CaCO3 reacts with ⇒ 32.6 g of H3PO4

   

unreacted agent is H3PO4

unreacted H3PO4 in grams = 24.9 g

                              in moles = 0.25 moles