Question

50 g of ice is added to 150 g of water at 50°C.
The resulting temperature will be :​

Answer 1

Correct Question :

50 g of ice at 0°C is mixed with 150 g of water at 50°C. The resulting temperature of the mixture will be ...

Answer :

Here,

Mass of water, m = 150g

Mass of ice, m' = 50g

Specific heat of water, s = 1 cal/g K

Latent heat of fusion of ice, L = 80 cal/g

Let T be the final temperature of the mixture$.$

★ Amount of heat lost by water

= m × s × ∆T

= 150 × 1 × (50 - T)

= 7500 - 150T

★ Amount of heat gained by ice

= (m' × L) + (m' × s × ∆T)

= (50 × 80) + [50 × 1 × (T - 0)]

= 4000 + 50T

According to principle of calorimetry

➠ Heat lost = Heat gained

➠ 7500 - 150T = 4000 + 50T

➠ 7500 - 4000 = 200T

➠ T = 3500/200

➠ T = 17.5 °C

∴ The reaulting temperature of mixture will be 17.5°C.