50 gram of ice at zero degree celsius is mixed with 50 gram of water at 60 degree Celsius final temperature of mixture will be
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The final temperature of the mix will be equal to 0°C.
When 50 gram ice at 0°C is mixed with 50 gram of water at 60°C then the water will loose heat . Whereas the ice will melt and gain heat . The mixture will finally reach an equilibrium temperature .
Mi - mass of ice = 50 gm
Mw - mass of water = 50 gm
L - latent heat of ice = 80 cal/gm
S - specific heat of ice = 1 cal/gm
For the mixture , Heat gained = Heat lost
50 × 80 > 60 × 50.
The value of heat gained by ice is greater , so some of the ice will not melt . Therefore the final temperature of the mixture is 0°C.
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Answer:10⁰C
Explanation:First ice must be converted to water
So mL=50×80=4000
Heat gained by ice =Heat lost by water
4000+50(1)(t-0)=50(1)(60-t)
50(80+t)=50(60-t)
80+t=60-t
20=2t
t=10⁰C
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