50 is divided into two parts such that the sum of their reciprocal is 1 ÷ 12 find the two parts
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hey friend your answer is here
x=4.8 then
50-x=50-4.8=45.2
please make me a brainlist answer for the question
x=4.8 then
50-x=50-4.8=45.2
please make me a brainlist answer for the question
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Given,x+y=50
x and y are the 2 parts of 50
Thus,x+y=50
x=50-y.................(i)
and, y=50-x
given,1/x+1/y=1/12
LCM=xy
(y+x)/xy=1/12
from (i)
(y+50-y)/[(50-y)y]=1/12
50/[50y-y^2]=1/12
1/[50y-y^2]=1/12*50
1/[50y-y^2]=1/600
by cross multiplication
50y-y^2=600
50y=600+y^2
0=[600+y^2]/50y
0=[50(12+y^2)]/50y
0=[12+y^2]/50y
0x50y=12+y^2
0=12+y^2
-y^2=12
y^2=-12
y=square root of 12
x and y are the 2 parts of 50
Thus,x+y=50
x=50-y.................(i)
and, y=50-x
given,1/x+1/y=1/12
LCM=xy
(y+x)/xy=1/12
from (i)
(y+50-y)/[(50-y)y]=1/12
50/[50y-y^2]=1/12
1/[50y-y^2]=1/12*50
1/[50y-y^2]=1/600
by cross multiplication
50y-y^2=600
50y=600+y^2
0=[600+y^2]/50y
0=[50(12+y^2)]/50y
0=[12+y^2]/50y
0x50y=12+y^2
0=12+y^2
-y^2=12
y^2=-12
y=square root of 12
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