Question

50 kg of an alloy of lead and tin contains 60%! lead how much lead must be added into it to make lead 75%?​

Answer 1

Answer:

Quantity of lead in 50 kg of alloy = 60% of 50 kg = kg = 30 kg.

Let the required quantity of lead to be added be x kg.

Then, weight of lead = (30 + x) kg.

And, weight of new alloy = (50 + x) kg.

Percentage of lead in new alloy = %

⇒ 4(30 + x) = 3(50 + x)

⇒ 120 + 4x = 150 + 3x

⇒ 4x - 3x = 150 - 120

⇒ x = 30

∴ quantity of lead to be added = 30 kg

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