Question

50 kg of Nitrogen and 10kg of hydrogen are mixed to produce ammonia.Calculate the ammonia formed.Identify the limiting reagent in this reaction​

Answer 1

Answer:

$50kg.n2 + 10kg.h2 = nh3 \\ n2 + 3h = 2nh3 \\ number \: of \: moles of \: n2 - \frac{50000}{28} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1785.7 \\ of \: h = \frac{15000}{2} = 5000 \\ 1666.67 = excess \\ \frac{2}{3} \times 5000 = \frac{10000}{3} = 3333.5 \times 17 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 56666.1 \: of \: nh3$