Question

50 ml of 0.1 M HCl is mixed with 50 ml of 0.05 M H2S04 . then resultant [ Cl― ] in the solution is​

Answer 1

Answer:

0.05M

Explanation:

Hcl = 0.1M and H2S04 = 0.05M

Volume of both HCl & H2SO4 = 50 ml = 0.05 L.

Thus, the number of moles of Cl- ions in HCl solution will be -

Moles of Cl- = 0.05 × 0.1

Moles of Cl- = 0.005 mol

The resultant concentration of [Cl-] in the mixture will be -

Concentration = Moles of Cl- / Total volume

[Cl-] = 0.005/(0.05+0.05)

[Cl-] = 0.05 M

Therefore, the resultant [Cl-] in the solution is 0.05 M.

Answer 2

Answer:

0.05M

Explanation:

number of solution of cl- is 0.05M