Question

50 ml of 1 m oxalic acid is shaken with 0.5g of wood charcoal. The final concentration of the solution after adsorption is 0.5 m . Amount of oxalic acid adsorbed per gram of charcoal is

Answer 1

50 ml of 1 m oxalic acid is shaken with 0.5g of wood charcoal. The final concentration of the solution after adsorption is 0.5 m . Amount of oxalic acid adsorbed per gram of charcoal is given as follows;

Oxalic Acid = 50ml = 0.05L

Initial Concentration 1M  and Final Concentration 0.5M

Therefore Initial Moles is 0.05 x 1 = 0.05moles  and final Moles is 0.05 x 0.5 = 0.025moles

Therefore the change in Moles= 0.05-0.025

= 0.025moles

 (Change in moles x molecular mass)/ grams of carbon

 (0.025 x 90.03)/0.5

= 4.5015 grams

Answer 2

Answer:

50ml of 1M oxalic acid is shaken with 0.5g of wood charcoal. The The final concentration of the solution after adsorption is 0.5M. Amount of oxalic acid absorbed per gm of charcoal is. 1g→6.32×0.5×1=6.3g.