Question

50 ml of 10N H2SO4, 25 ml of 12N HCl and 40 ml of 5N HNO3 were mixed together and the volume of the mixture was made 1000 ml by adding water.the normality of the resulting solution will be

Answer 1

ans is 1N.......see the pic

Answer 2

To find the normality of the solution $=\frac{\left(N_{1} V_{1}\right)+\left(N_{2} V_{2}\right)+\left(N_{3} V_{3}\right)}{N e t \text\ {Volume}}$

The normality of a mixture solution is determined by the ratio of the sum of the product of the normality and volume of the individual solution to the net volume of the mixture solution.

$\begin{array}{l}{\text { Normality of the } H_{2} S O_{4} \text { solution, } N_{1}=10 N} \\ {\text { Volume of the } H_{2} S O_{4} \text { solution, } V_{1}=50 \mathrm{ml}} \\ {\text { Normality of the } H C L \text { solution, } N_{2}=12 \mathrm{N}} \\ {\text { Volume of the } H C L \text { solution, } V_{2}=25 \mathrm{ml}}\end{array}$

$\begin{array}{l}{\text { Normality of the } H N O_{3} \text { solution, } N_{3}=5 N} \\ {\text { Volume of the } H N O_{3} \text { solution, } V_{3}=40 m l} \\ {\text { Volume of the mixture to be made, } V_{n e t}=1000 m l}\end{array}$

$\begin{array}{r}{\text { Then, Normality of the solution= } \frac{(10 \times 50)+(12 \times 25)+(5 \times 40)}{1000}} \\ \\ {=\frac{500+300+200}{1000}} \\ \\ {=\frac{1000}{1000}} \\ \\ {=1}\end{array}$

The normality of the mixture solution is, N = 1.