Question

50 ml of a sample water consumed 15 ml of 0.01 EDTA before boiling and 5 ml of the same EDTA after boiling. calculate the degree of hardness, permanent hardness and temporary hardness

Answer 1

Explanation:

50ml of water sample=15ml of 0.01M EDTA

=\frac{50*100}{50} ml of 0.01 EDTA=300ml of 0.01M EDTA

=2*300ml of 0.01 N EDTA

=600 ml or 0.6 L of 0.01 eq. of CaCO3

=0.6*0.01*50g CaCO3 eq.

Then the total hardness=0.30g or 300mg of CaCO3 eq=300mg/L or ppm

now 50 ml of boiled water=5 ml of 0.01 M EDTA

1000ml of boiled water=\frac{5*1000}{50} ml of 0.01 M EDTA

=100 mL of 0.01 M EDTA

=200ml or 0.2 L of 0.01 N EDTA

=0.2*0.01*50 g of CaCO3 eq

=0.1 g or 100mg of CaCO3 eq

permanent hardness=100mg/L or ppm

Temporary hardness=300-100= 200ppm

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