Math, asked by sn8593791, 9 months ago

if alpha and beta are the zeroes of quadratic polynomial of p(x)=4x-5x-1 find the value of alpha square beta +alpha beta square

Answers

Answered by Anonymous
1

Answer:

Hey!

Given polynomial :- 4x²-5x-1

and alpha beta are it's zeros !

• Sum of Zeros =

= \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }

\alpha + \beta = \frac{5}{4}

• Product of Zeros =

\frac{constant \: term}{coeff. \: \: of \: {x}^{2} }

\alpha \beta = \frac{ - 1}{4}

# To find

{ \alpha }^{2} \beta + \alpha { \beta }^{2}

\alpha \beta ( \alpha + \beta )

\frac{ - 1}{4} \times \frac{5}{4} = \frac{ - 5}{16}

Hence , value is -5/16

Answered by jayaramcharan
0

Answer:

4x-5x-1=0

1x-1=0

1x=1

x=1÷1

x=1

x

zeros are 1,1 equivalent zeros of quadratic polynomial

alpha =1

beta =1

alpha square=1^2

bheeta square=1^2

alpha square+bheeta square=1^2+1^2

=1+1=2

your answer is 2

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