if alpha and beta are the zeroes of quadratic polynomial of p(x)=4x-5x-1 find the value of alpha square beta +alpha beta square
Answers
Answered by
1
Answer:
Hey!
Given polynomial :- 4x²-5x-1
and alpha beta are it's zeros !
• Sum of Zeros =
= \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} }
\alpha + \beta = \frac{5}{4}
• Product of Zeros =
\frac{constant \: term}{coeff. \: \: of \: {x}^{2} }
\alpha \beta = \frac{ - 1}{4}
# To find
{ \alpha }^{2} \beta + \alpha { \beta }^{2}
\alpha \beta ( \alpha + \beta )
\frac{ - 1}{4} \times \frac{5}{4} = \frac{ - 5}{16}
Hence , value is -5/16
Answered by
0
Answer:
4x-5x-1=0
1x-1=0
1x=1
x=1÷1
x=1
x
zeros are 1,1 equivalent zeros of quadratic polynomial
alpha =1
beta =1
alpha square=1^2
bheeta square=1^2
alpha square+bheeta square=1^2+1^2
=1+1=2
your answer is 2
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