Question

9. Calculate the value of the acceleration due to gravity
at a place 3,200 km above the surface of the earth.
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Answer 1

Hey here is the answer hope it helps.........,

Assume:

    h= 3200km = 3200000m = 3.2 x10^6

    R= 6400km = 6400000m = 6.4 x 10^6

    g= 9.8m/s^2

We know that-

          g'= g[R^2/(R+h)^2]

             = 9.8(40.96 x 10^12/92.16 x 10^12)

             = 9.8 x 4/9

             = 4.355m/s^2 ~ 4.4m/s^2

Thus, value of g at a place 3200km above surface of the earth is 4.4m/s^2.

Hope it helps mark as brainliest please