Math, asked by rajuarora87, 11 months ago

A path 3.5 m wide runs inside along the boundary of a square field whose side is 65 m . find the area of the path also find the cost of manuring the rest of the field at the rate of rupees 25 per square meter​

Answers

Answered by saneyashu
6

Answer:959 sq. m is the area of the pathCost written in explanationStep-by-step explanation:Side of square field = 65 mWidth of path =  3.5 m Area of the field= Side*Side                           = 65*65                           = 4225 sq. mArea of the field including path = Side * Side                                                     = (65+3.5+3.5) * (65 + 3.5+ 3.5)                                                     = 65 + 7 * 65+7                                                     =  72*72                                                     =  5184 sq. mArea of path= 5184 - 4225                     = 959 sq. cm Cost for manuring the rest of the field (excluding path) = area * rate                                                                                            =  4225*25                                                                                            = ₹ 105625Cost for manuring the rest of the field (including path) = 5184 * 25                                                                                           = ₹ 129600Cost for manuring the path only = 959 * 25                                            

Answered by renuagrawal393
7

Answer:

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