Question

D is a point on the side BC of triangle ABC such that AD = AC. Show that AB > AD.

Answer 1

Answer:

Step-by-step explanation:

In the above figure, AD = AC ( given)

So, < d = < c

In triangle ABD

Exterior angle d > angle b ( as exterior angle is greater than its interior opposite angle.)

But < d = < c

=> <c greater than <b

=> AB > AC ( as, side opposite to greater angle is greater in a triangle)

But, AC = AD

So, AB > AD

[ Hence Proved]

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