50 mm diameter disc is to be punched out from a carbon steel sheet 1.0 mm thick. The diameter of the punch should be. (Take clearance as 3% of disc thickness).
49.94 mm
50.00 mm
50.075 mm
None of these
Answers
answer : 49.94mm
explanation : using formula,
The diameter of punch = diameter of disc - 2 × clearness
here it is given that ,
diameter of disc = 50mm
and clearance = 3% of disc thickness
= 3% of 1mm [ as thickness of disc = 1mm]
= 3 × 1/100 = 0.03 mm
so, The diameter of punch = 50mm - 2 × 0.03mm
= 50mm - 0.06mm
= 49.94 mm
hence, The diameter of punch should be 49.94 mm.
Answer:
Option 1st is correct that is 49.94 mm
Step-by-step explanation:
Given: 50 mm Diameter Disc and 1 mm thick
To find: Diameter of the punch
The diameter of punch = diameter of disc - 2 × clearness
here it is given that ,
clearance = 3% of disc thickness
= 3% × 1 = 3/100 × 1 = 0.03 mm
Thus, we get
The diameter of punch = 50 - 2 × 0.03 = 50 - 0.06 = 49.94 mm
Therefore, Option 1st is correct that is 49.94 mm