Question

plz answer......faster ​

Answer 1

First of all, Square on both sides.

(tanTheta-cotTheta)^2=1^2

tan^2theta+cot^2theta-2tancot=1

tan^2theta+cot^2theta=1+1=2.

Answer 2

★GOOD MORNING★

Let theta = x

Tan x - Cot x = 1

SQUARING BOTH SIDE'S

( Tan x - Cot x )² = 1²

=>

Tan² x + Cot² x - 2 = 1

Becoz ( a - b )² = a² + b² - 2ab And

Tan x = 1/Cotx

=>

Tan² x + Cot² x = 1 + 2

=>

Tan² x + Cot² x = 3