50 N of force is applied on an object through 5m at an angle of 75°,the body displaces 10 m.Calculate the work done.Give reasonsfor your answer.......
danishjoshi111:
Yaar Bas kr .. (You have made the question yourself )
yr pr agar koi hor question khole galat answer thodi naa mille ohnu
Tu hi dede answer .
Kr himmat fer aj
U have 5 minutes..
Challenge accepted .
Answers
Answered by
2
please see the attached document ....
Attachments:
ya but their is another formula for work done w = f.scos theta
that's not the matter , let us ignore cos theta.
I know all the formulaes related to work.
but when an angle forms between force applied and displacement then we use w = fscostheta
let the force applied at an angle of 0°
then w = fs cos theta ...w=50*5*1 = 250 j
But the displacement is 10m
but the force is applied only through 5m of distance !!!!
i think Ashutosh should specify the mass of the object .
Danishjoshi111 consider the mass to be 10 kg.and if it is not specified u can take it as a variable......(m)..
Similar questions