50 ohm and 100 ohm resistors are connected in series. this connection with a battery of 2.4 . when a voltmeter of 100 ohm resistance is connected across 100 ohm resistors then the reading of the voltmeter will be?
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r1 = 50 ohm
r2 = 100 ohm
Voltmeter connected in parallel to r2
Voltmeter resistance Rv = 100 ohm
So parallel resistance = Rp
1/Rp= 1/r2 + 1/Rv
1/Rp = 1/100 + 1/100
Rp = 50 ohm
Rn - net resistance
r1 + Rp = 50 + 50 = 100 ohm
net current = 2.4/100 = 0.024 A
Voltmeter reading = net current * Rp = 0.024*50 = 1.2 V
Voltmeter reading = 1.2V
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