Question

50 points
...
A particle is moving such that its position
coordinates (x, y) are
(2 m, 3 m) at time t = 0,
(6 m, 7 m) at time t = 2 s and
(13 m, 14 m) at time t = 5 s.
Average velocity vector (Var) from t = 0 to t = 5 sec??​

Answer 1

Answer:

given ,

position of moving particles =

2m,3m at time t = 0

6m,7m at time t =2sec

13m , 14 at time t =5sec

according to Question -

Average velocity = total moving of particles/time

Correct option (d) 11/5(i+j)

Explanation:

At time t = 0,

the position vector of the particle is At time t = 5 s, a-particle-is-moving-such-that-its-position-coordinates-x-y-are-2-m-3-m .

Hope it's helpful for you .

Answer 2

Answer:

$\huge\mathfrak\red{Given}$

A particle is moving such that its position

coordinates (x, y) are

(2 m, 3 m) at time t = 0,

(6 m, 7 m) at time t = 2 s and

(13 m, 14 m) at time t = 5 s.

Average velocity = Total moving of particles \time .

correct answer - d

11\5 (i+j)

hope it's helpful for you .

$\huge\mathfrak\green{Thanks}$