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Answers
Answer:
Given,
q(y) = 7y² – (11/3)y – 2/3
We put q(y) = 0
⇒ 7y² – (11/3)y – 2/3 = 0
⇒ (21y² – 11y -2)/3 = 0
⇒ 21y² – 11y – 2 = 0
⇒ 21y² – 14y + 3y – 2 = 0
⇒ 7y(3y – 2) – 1(3y + 2) = 0
⇒ (3y – 2)(7y + 1) = 0
This gives us 2 zeros, for y = 2/3 and y = -1/7
Hence, the zeros of the quadratic equation are 2/3 and -1/7.
Now, for verification
Sum of zeros = – coefficient of y / coefficient of y²
2/3 + (-1/7) = – (-11/3) / 7
-11/21 = -11/21
Product of roots = constant / coefficient of y²
2/3 x (-1/7) = (-2/3) / 7
– 2/21 = -2/21
Therefore, the relationship between zeros and their coefficients is verified.
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PLZZ MARK AS BRAINLIEST
Answer:
Distance is a scalar quantity whereas displacement is a vector quantity. Distance is the total path covered by the body and displacement is the shortest path covered by the body. ... Distance doesn't decrease with time whereas displacement decreases. Distance is always equal to or greater than the displacement.
Step-by-step explanation:
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