Question

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Hi brainly users,

Here is your today's question :-

Find the dimension of a & b in the following vanderwall equation. Here P - pressure, T - temperature, v - volume, R - gas constant.

$[ \: P \: + \: \frac{a}{ {v}^{2} } \: ] \: ( \: v \: - \: b \: ) \: = \: R \: T$​

Answer 1

Explanation:

unit of a is atm L² mol–²

unit of b is L mol–¹

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Answer 2

P + a/V2) (V - b) = RT P is pressure, V is volume and T is temperature.

[P] = [F/A] = [MLT −2/L2] = [ML−1T −2] [V] = [L3]

We cannot add or subtract quantities of different dimensions.

Therefore [P] = [a/V2] ⇒ [a] = [PV2] = [ML−1T −2 L6] = [M L5 T −2] ∴ [a] = [M L5 T −2]

Similarly, [b] = [V] = [L3]