Question

The sum of length,breadth and height of cuboid is 22 cm and the length of its diagonal is 14 cm. then What is the surface area of cuboid =?​

Answer 1

Answer:

470cm^2

Step-by-step explanation:

l+b+h = 22cm

l^2+b^2+h^2= 14

lb+bh+lh=?

(l+b+h)^2 = (l^2+b^2+h^2) + 2(lb+bh+lh)

22×22 = 14 + 2(lb+bh+lh)

2(lb+bh+lh) = 484 - 14 = 470

Note :

diagonal = l^2+b^2+h^2

Answer 2

Surface area of cuboid is 288 cm².

Step-by-step explanation:

Given : The sum of length,breadth and height of cuboid is 22 cm and the length of its diagonal is 14 cm.

To find : What is the surface area of cuboid ?​

Solution :

Let length =l , breadth = b and height =h of the cuboid.

The sum of length,breadth and height of cuboid is 22 cm.

i.e. $l+b+h=22$

Squaring both side,

$(l+b+h)^2=484$ ....(1)

The length of its diagonal is 14 cm.

i.e. $\sqrt{l^2+b^2+h^2}=14$

Squaring both side,

$l^2+b^2+h^2=196$ .....(2)

The surface area of the cuboid is given by,

$SA=2(lb+bh+hl)$

$SA=(l+b+h)^2-(l^2+b^2+h^2)$

$SA=484-196$

$SA=288$

Surface area of cuboid is 288 cm².

#Learn more

The sum of the length,breadth and height of a cuboid is 38cm and the length of its diagonal is 22cm. Find the surface area of cuboid.

https://brainly.in/question/67653