50 points. If all the coefficients of a polynomial are positive, then are all the roots negative? Explain(Don't explain if it is just a fact) (Assume that roots are real)
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Answered by
5
Let the quadratic equation we will deal with is ax²+bx+c=0
here a,b,c are positive.....
So sum of roots = -b/a
Product of roots = c/a
hence sum is negative it is evident that roots are negative.
Let us look at a demostration with an example
x²+6x+9=0
so sum of roots = -6/1=-6
product of roots=9/1
later we find (x+3)²=0
x= -3,-3
hope helped !
here a,b,c are positive.....
So sum of roots = -b/a
Product of roots = c/a
hence sum is negative it is evident that roots are negative.
Let us look at a demostration with an example
x²+6x+9=0
so sum of roots = -6/1=-6
product of roots=9/1
later we find (x+3)²=0
x= -3,-3
hope helped !
Answered by
10
★ QUADRATICS RESOLUTION ★
GENERAL QUADRATIC EQUATION →→→
ax² + bx +c =0
Here, coefficients of polynomial are positive
For possible combination about negative roots conclude that a>0, b>0 , where c resides as constant ...
Acquired behaviour of quadratic function is
b² - 4ac =0
so that we can obtain perfect square as roots
in variable x .
it's applicable condition for acquiring perfect squares , with both the roots either positive or negative
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
GENERAL QUADRATIC EQUATION →→→
ax² + bx +c =0
Here, coefficients of polynomial are positive
For possible combination about negative roots conclude that a>0, b>0 , where c resides as constant ...
Acquired behaviour of quadratic function is
b² - 4ac =0
so that we can obtain perfect square as roots
in variable x .
it's applicable condition for acquiring perfect squares , with both the roots either positive or negative
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
AdityaSharma111:
nice bhai
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