Question

50 POINTS

please answer this 2 question fast​

Answer 1

check the attachment

hope it helps

Answer 2

hey mate

here is the answer...

Answer:

24-

|x²+x+1|+|2x-3|=4x

=>|x²+3x-2|=4x

=>|x²-x-2|=0

=>|x²-2x+x-2|=0

=>|x(x-2)+1(x-2)|=0

=>|(x+1)(x-2)|=0

thus,

|(x-2)|=0 and |(x+1)|=0

hence,
x=2 and -1.

25-

|2^x-1|+|2^x+1|=2

=>|2*2^x-1+1|=2

=>|2^(x+1)|=2

=>2^(x+1)=2¹

=>(x+1)=1

=>x+1=1

=>x=0

thus,

x=0