Physics, asked by Anu726, 11 months ago

50 points

please don't give wrong answer

options

1) r square
2)r
3)1/r
4)1/rsquare

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Answers

Answered by Blaezii
10

Answer :

Option => 2

"R"

Explanation :

Given :

The electric potential at a point (x , y).

The Plane is given by V = - k x y.

The field intensity at a distance r in this plane.

To Find :

The field intensity at a distance r in this plane, From the origin varics as.

Solution :

According to the Question,

\sf\\ \\\implies E_x = \dfrac{\partial\;V}{\partial\;x} = ky

\sf\\ \\\implies E_y = \dfrac{\partial\;V}{\partial y} = kx

\sf\\ \\\implies \overrightarrow{E} = E_x \;\hat{i} + E_y\; \hat{j}\\ \\ \\

\sf\\ \\\implies \overrightarrow{E}=E_y \;\hat{i} + K_x\; \hat{j}\\ \\ \\

\sf\\ \\\implies |\overrightarrow{E}| =\sqrt{k^2\;y^2+k\;x^2}}

\sf \\ \\\implies |\overrightarrow{E}| =k\sqrt{x^2+y^2}

\sf\\ \\\implies k\;r\\ \\\implies |\overrightarrow{E}| = \infty\; r

Answered by yadavankit127
0

Answer:

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