50 points
plz answer it urjent
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hope it helps!!
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suppose √(a+2b) = m
√(a-2b) = n
=> (m+n)/(m-n)
=> (m+n)²/(m²-n²)
=> ((m²+2mn+n²)/(m²-n²)
=> (a+2b + 2√(a²-4b²) + a - 2b) /(a+2b-a+2b)
=> 2(a+√(a²-4b²)/4b
=> x = (a+√(a²-4b²))/2b
=> bx² - ax + b
= (a+√(a²-4b²))²/4b - (a²+a√(a²-4b²))/2b + b
= ( a² + 2a√(a²-4b²) + a² - 4b² - 2a² - 2a√(a²-4b²) + + 4b²)/4b
= 0
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