Question

50 points question..☺

In a examination Ram score 40% of full marks and failed by 10 marks.
in a same examination sohan score 60% marks of full marks and score 15 more than passing marks.

Then find the passing marks.

✔Answer it,✔

❎Don't spam❎

Answer 1

Hey Mate !

Here is your solution :

Let the full marks is x and passing marks is y.

A/Q,

Ram scored 40% of full marks but failed by 10 marks.

So, passing marks will be 40% of full marks + 10 marks.

=> ( 40% of x ) + 10 = y

=> [ ( 40/100 ) x ] + 10= y

=> [ ( 2/5 ) x ] + 10 = y

=> ( 2x/5 ) + 10 = y ----------------- ( 1 )

Now,

Sohan scored 60% of full marks and get 15 marks more than passing marks.

So,

Pass marks will be 60% of full marks - 15.


=> [ 60% of x ] - 15 = y

=> [ ( 60/100 ) x ] - 15 = y

=> [ ( 3/5 ) x ] - 15 = y

=> ( 3x/5 ) - 15 = y ---------------- ( 2 )

From ( 1 ) and ( 2 ), we get ;

=> ( 2x/5 ) + 10 = ( 3x/5 ) - 15

=> 10 + 15 = ( 3x/5 ) - ( 2x/5 )

=> 25 = x/5

=> 25 × 5 = x

=> 125 = x

=> x = 125

By substituting the value of x in ( 1 ),

=> ( 2x/5 ) + 10 = y

=> [ ( 2 × 125 ) /5 ] + 10 = y

=> ( 2 × 25 ) + 10 = y

=> 50 + 10 = y

=> 60 = y

=> y = 60


Hence,

Full marks = x = 125

Passing marks = y = 60

===============================

Hope it helps !! ^_^

Answer 2

Here is your solution :

Let the full marks is x and passing marks is y.

A/Q,

Ram scored 40% of full marks but failed by 10 marks.

So, passing marks will be 40% of full marks + 10 marks.

=> ( 40% of x ) + 10 = y

=> [ ( 40/100 ) x ] + 10= y

=> [ ( 2/5 ) x ] + 10 = y

=> ( 2x/5 ) + 10 = y ----------------- ( 1 )

Now,

Sohan scored 60% of full marks and get 15 marks more than passing marks.

So,

Pass marks will be 60% of full marks - 15.


=> [ 60% of x ] - 15 = y

=> [ ( 60/100 ) x ] - 15 = y

=> [ ( 3/5 ) x ] - 15 = y

=> ( 3x/5 ) - 15 = y ---------------- ( 2 )

From ( 1 ) and ( 2 ), we get ;

=> ( 2x/5 ) + 10 = ( 3x/5 ) - 15

=> 10 + 15 = ( 3x/5 ) - ( 2x/5 )

=> 25 = x/5

=> 25 × 5 = x

=> 125 = x

=> x = 125

By substituting the value of x in ( 1 ),

=> ( 2x/5 ) + 10 = y

=> [ ( 2 × 125 ) /5 ] + 10 = y

=> ( 2 × 25 ) + 10 = y

=> 50 + 10 = y

=> 60 = y

=> y = 60


Hence,

Full marks = x = 125

Passing marks = y = 60