Question

(50 points) solve.....

Answer 1

$\textbf{\huge{ANSWER}}$

For each of these relations on the set [1, 2, 3, 4], we can decide whether it is

1. reflexive,
2. symmetric,
3. antisymmetric,
4. transitive.

;- [(2, 2),(2, 3),(2, 4),(3, 2),(3, 3),(3, 4)]

• Not reflexive because we do not have (1, 1), (3, 3), and (4, 4).

• Not symmetric because while we we have (3, 4), we do not have (4, 3).

• Not antisymmetric because we have both (2, 3) and (3, 2).

• Thus , Transitive because if we have (a, b) in this relation, then a will be either 2 or 3. Then (2, c)and (3, c) are in the relation for all c 6= 1.

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Answer 2

Answer:

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