Question

✔️✔️50 points !!!✔️✔️

sum of the digits of two digit number is 9.the number obtained by inter changing the digit is 18 more than twice the original number the original number is :

a)72
B)27
C)63
d)36

❌❌NO SPAM ❌❌​

Answer 1

$<b><marquee>HEY!!</marquee></b>$

$\fbox{HERE'S YOUR ANSWER}$

⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️

$\huge{ANSWER}$

The answer is 27

EXPLANATION :

let's say X is the unit digit and Y is the tenth digit.

y+x=9 -> y=9-x

10x+y =10y+x+27

10x+9-x=10(9-x)+x+27

10x+9-x=90-10x+x+27

18x=108

x=6

so y=3

let's check

63-39=27

27=27(correct)

THANK YOU

PLEASE MARK ME AS A BRAINLIST

HAVE A GREAT DAY!!!

i am in need of brainlist please mark

Answer 2

Answer:

The original number is 27

Step-by-step explanation:

Let the first number be x

We know that the sum of the digits is 9.

Therefore, first number +  second number = 9

The first number is in tens place. So it is 10x and second number is 9-x.

When we add this we get, 10x + 9-x = 9x-9, this is the original numer.

By the question if we inverse this number ,

tens place will be 10(9-x) and ones place will be x

When we add this we get, 90- 10x+x = 90-9x

Now, the queststion say,

       90-9x = 2(9x - 9) +18

Therefore, 90-9x = 18 +36

       therefore, x = 2

Now, let us substiute the 2 in the place of x in the original number

Thus, tens place is 20 and ones place is 9-2 = 7

Adding this we get the number 27

HOPE THIS HELPS YOU.. THANKS FOR READING!!!