Math, asked by dia190, 10 months ago

50 points !!!!!!!


4 + 2 \sqrt{3}
kese hua ​

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Answered by Anonymous
2

Answer:

{\bold{\boxed{4 + 2 \sqrt{3}}}}

Step-by-step explanation:

7 -  \sqrt{3}  - x = 3 +  \sqrt{3}

now taking everything equivalent to x

so we get,

 - x =  - 7 + 3 +  \sqrt{3}  +  \sqrt{3}

now { \sqrt{3} } will get twice of { \sqrt{3} }

so we have now,

 - x =  - 4 + 2  \sqrt{3}

now variable x negative sign will pass on to the numeric term

x =  - ( - 4 + 2 \sqrt{3} )

so the final answer will be

{\bold{\red{\boxed{x = 4  - 2 \sqrt{3}}}}}

Answered by Anonymous
22

\huge\boxed{Question}

4 + 2 \sqrt{3}

\huge{\pink {\sf\underline{Answer}}}

=] 7-√3-x = 3+√3

now taking all the constant one side and variable one side we get

=] -x = 3+ 3-7+3

=] -x= -7 +3+3+3

So,

-x = -4+23

negative sign of X will transfer to RHS we get

=] x = -(-4+23)

=] x = 4-23

thanks ♥️

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