Question

( ･ิϖ･ิ)50 Points( ･ิϖ･ิ)


The Displacement of a Particle moving along X Axis where x=18t+5t^2.

Calculate

1)Instantaneous velocity at t=2 second

2) Average velocity b/w t=2 Sec to 3 sec.

3) Acceleration!​

Answer 1

Answer:

The answer is provided below :-

Answer 2

SOLUTION

Using differentiation

x= 18t+ 15t^2

$= > \frac{dx}{dt} = 18 + 10t$

v= 18+10t

1️⃣. Instantaneous Velocity:

at t=2 seconds

=) v= 18+ 10× 2

=) v= 18+ 20

=) v= 38m/s

at t= 3sec.

=) v= 18+ 10× 3

=) v= 18+ 30

=) v= 48m/s

2️⃣. Average Velocity:

$= > Vav = \frac{38 + 48}{2} \\ \\ = > Vav = \frac{86}{2} = 43m/s$

3️⃣. Acceleration:

$= > \frac{dx}{dt} = 10 \\ \\ = > a = 10$

a= 10m/s^2

hope it helps ☺️