50 points
.
.
Two balls of masses 5kg and 2kg are approaching each other with velocities 5m/s and 1m/s respectively. After collision they coalesce together. calculate velocity of combined bell. Also calculate loss of KE.
Answers
Answered by
0
Answer:
By momentum conservation,
2(4)−4(2)=2(−2)+4(ν
2
)
⟹ν
2
=1m/s.
b) e=
Velocityofapproach
Velocityofseparation
=
4−(−2)
1−9−2)
=
6
3
=0.5
c) At the maximum deformed state, by conservation of momentum, common velocity is ν=0
J
D
=m
2
(ν−u
2
)=4[(0−(−2)]=8Ns
d) Potential energy at the maximum deformed state,
U= loss in kinetic energy during defirmation
or U=(
2
1
m
1
u
1
2
+
2
1
m
2
u
2
2
)−
2
1
(m
1
+m
2
)ν
2
=(
2
1
2(4)
2
+
2
1
4(2)
2
)−
2
1
(2+4)(0)
2
=24J
e) J
R
=m
2
(ν
2
−ν)=4(1−0)=4Ns
also J
R
=eJ
D
=0.5×8=4Ns
Answered by
0
use principle of comservation of momentum.
and then use the formula for kinetic engery..
Let v be the common velocity.
Applying conservation of momentum
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