Question

50 pointsss


find the zeroes of zereos of x^2-x-6

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Answer 1

Answer:

X^2-x-6

X^2-3x+2x-6

X(x-3)+2(x-3)

(X+2)(x-3)=0

X=-2 or x=3

Answer 2

x² - x - 6

__________ [ GIVEN ]

• We have to find zeros of x² - x - 6

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→ x² - x - 6

The above equation is in the form ax² + bx + c

We have to find a number whose sum is 'b' i.e. (-x) and product is 'c' i.e. (-6)

→ x² - x - 6

→ x² - (3x - 2x) - 6

→ x² - 3x + 2x - 6

→ x(x - 3) +2(x - 3)

→ (x + 2) (x - 3)

We have to find zeros. Means (x + 2) (x - 3) must be equal to 0.

→ (x + 2) (x - 3) = 0

→ x = -2, +3

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- 2 and + 3 are zeros the of x² - x - 6.

________ [ ANSWER ]

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